The sum of the interior angles of a pentagon is... - JAMB Mathematics 2004 Question
The sum of the interior angles of a pentagon is 6x + 6y. Find y in the terms of x
A
y = 90 - x
B
y = 150 - x
C
y = 60 - x
D
y = 120 -x
correct option: a
6x + 6y = (n - 2) 180
6x + 6y= (5 - 2) 180
6(x + y) = 3 * 180
x + y = (3 * 180)/6
x + y = 90o
y = 90 - x
6x + 6y= (5 - 2) 180
6(x + y) = 3 * 180
x + y = (3 * 180)/6
x + y = 90o
y = 90 - x
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